[Paul Weinberger]

I am running the example myfacesrlc\src\org\apache\myfaces\examples\misc\FileUploadForm.java
with the following settings on WindowsXP and Java 1.5 and Tomcat-5.5.17 and observed the following
when using the Tomahawk ext to upload files: Tomahawk seems to have its own ideas about what
to name the files when uploaded. I need access to the files to manipulate them after upload
and need to know what they are named and where they are.

If I upload a file like abc.jpg it reports back fine in the return page as the correct image and the right name,
but I need to fix two things and I can’t seem to trap for them in the debugger to help figure out where to make
the changes.

1. The file name is always changed to upload_A NUMBER.tmp like this upload_00000007.tmp rather than the
real name of the file.

2. What ever directory name that I set in the web.xml for uploadRepositoryPath ends up on the root
of my C drive rather than the root of the application?
I understand from reading that there may be some involvement with the java.io.tmpdir but I am not sure.

It would be VERY helpful if some one can tell me how to make it write to a relative directory in the application
context off the application root in tomcat, and how do I best make it write the file name that I want the first time
or at least re-copy it to the correct directory with the right name.
I have tried to set the debugger to catch when the change is happening but I have not been successful.

with WebRoot\fileupload.jsp
…
<h:form id=”form1″ enctype=”multipart/form-data” >
<h:outputText value=””/>
<h:outputText value=”#{example_messages[‘fileupload_gimmeimage’]} “/>
<t:inputFileUpload id=”fileupload”
accept=”image/*”
value=”#{fileUploadForm.upFile}”
storage=”file”
styleClass=”fileUploadInput”
required=”true”
maxlength=”200000″/>
<h:message for=”fileupload” showDetail=”true” />
<f:verbatim><br></f:verbatim>
<h:outputText value=”#{example_messages[‘fileupload_name’]}”/>
<h:inputText value=”#{fileUploadForm.name}”/>
<h:commandButton value=”#{example_messages[‘fileupload_button’]}” action=”#{fileUploadForm.upload}” />
</h:form>
…

web.xml …
<filter>
<filter-name>extensionsFilter</filter-name>
<filter-class>org.apache.myfaces.webapp.filter.ExtensionsFilter</filter-class>
<init-param>
<description>Set the size limit for uploaded files.
Format: 10 – 10 bytes
10k – 10 KB
10m – 10 MB
1g – 1 GB</description>
<param-name>uploadMaxFileSize</param-name>
<param-value>100m</param-value>
</init-param>
<init-param>
<description>Set the threshold size – files
below this limit are stored in memory, files above
this limit are stored on disk.

Format: 10 – 10 bytes
10k – 10 KB
10m – 10 MB
1g – 1 GB</description>
<param-name>uploadThresholdSize</param-name>
<param-value>1k</param-value>
</init-param>
<init-param>
<description>Set the path where the intermediary files will be stored.</description>
<param-name>uploadRepositoryPath</param-name>
<param-value>/uploadLocation</param-value>
</init-param>
</filter>

…

Thank you very much in advance.

[Riyad Kalla]

Moving to OT > Soft Dev

[Paul Weinberger]

Close issue.
The answer is to use
value=”#{fileUploadForm.upFile}”

sets the value of file name in the backing bean. upFile is basically a setter for a field of type UploadedFile.

Use the following to grab the input stream
upFile.getInputStream()
That way you don’t have to worry about the file name.

[Riyad Kalla]

MDOT, Thank you for following up for other users that are trying to do the same work, very helpful.

[Author]

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