- This topic has 1 reply, 2 voices, and was last updated 17 years, 2 months ago by Loyal Water.
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vljc2004MemberHi!, i’m follow the tutorial hibernate and spring, but i’m want make operate via web with my server tomcat.
Whereby , im create this class:
public class ControllerUser implements Controller { public ModelAndView handleRequest(HttpServletRequest res, HttpServletResponse arg1) throws Exception { // TODO Auto-generated method stub //ApplicationContext ctx = new ClassPathXmlApplicationContext("applicationContext.xml"); //ApplicationContext ctx = WebApplicationContextUtils.getRequiredWebApplicationContext(this.getServletContext()); //BeanFactory beanfactory = new XmlBeanFactory(new ClassPathResource("applicationContext-servlet.xml")); /*BeanFactory beanFactory = new XmlBeanFactory(new ClassPathResource( "applicationContext-servlet.xml",getClass()));*/ //Persistence persistence = (Persistence) beanfactory.getBean("persistance"); Persistence persistence=new Persistence(); String dato=res.getParameter("dato"); Usuarios user=new Usuarios(); user.setNombre(dato); user.setCorreo("hola"); user.setIdUsuario(1); persistence.save(user); HashMap datos= new HashMap(); datos.put("resp", dato); System.out.print(datos); return new ModelAndView("index.jsp","m",datos); } }
Have very line in coment, before im try link my applicationcontext-servle but i’m not can make the link :s.
The message error is :
org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [applicationContext-servlet.xml]; nested exception is java.io.FileNotFoundException: class path resource [applicationContext-servlet.xml] cannot be opened because it does not exist
Loyal WaterMemberThis seems like a framework specific question/error. Can you cross post this on the spring forums as well.
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